For the given arrangement, what will be the distance of the final image from the third lens?
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29/12/2021 1:24 pm
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For the given arrangement, what will be the distance of the final image from the third lens?
(a) 75
(b) 30
(c) ∞
(d) 40
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29/12/2021 1:36 pm
Correct answer: (b) 30
Explanation:
Lens formula,
\(\frac{1}{v}\) - \(\frac{1}{u}\) = \(\frac{1}{f}\)
\(\frac{1}{v}\) - \(\frac{1}{-30}\) = \(\frac{1}{10}\)
\(\frac{1}{v}\) = \(\frac{1}{10}\) - \(\frac{1}{30}\)
⟹ \(\frac{1}{v}\) = \(\frac{3-1}{30}\)
v = 15 cm
Now we have u = +10 cm
\(\frac{1}{v}\) - \(\frac{1}{10}\) = \(\frac{1}{-10}\)
⟹ \(\frac{1}{v}\) = \(-\frac{1}{10}\) + \(\frac{1}{10}\)
⟹ v = ∞
It means for the third lens, rays are coming parallel to the principal axis, hence, an image will be formed at the focus of the third lens.
Thus, V = + 30 cm (from third lens)
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