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07/01/2022 2:02 pm
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For a transistor α and β are given as α = \(\frac{I_C}{I_E}\) and β = \(\frac{I_C}{I_B}\).
Then the correct relation between α and β will be
(1) α = \(\frac{1- \beta}{\beta}\)
(2) β = \(\frac{\alpha}{1-\alpha}\)
(3) αβ = 1
(4) α = \(\frac{\beta}{1-\beta}\)
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1 Answer
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07/01/2022 2:11 pm
Correct answer: (2) β = \(\frac{\alpha}{1-\alpha}\)
Explanation:
α = \(\frac{I_C}{I_E}\), β =\(\frac{I_C}{I_B}\);
IE = IC + IB
α = \(\frac{I_C}{I_C + I_B}\) = \(\frac{\frac{I_C}{I_B}}{\frac{I_C}{I_B}+1}\)
= \(\frac{\beta}{\beta +I}\) +1+ \(\frac{1}{\beta}\) = \(\frac{1}{\alpha}\)
= \(\frac{1}{\beta}\) = \(\frac{1 - \alpha}{\alpha}\)
\(\beta\) = \(\frac{\alpha}{1 - \alpha}\)