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Find the Binding energy per nucleon for 120^50Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U

Physics

Last Post by nikhil04 4 years ago

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18/09/2020 6:38 pm

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aditi07

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Find the Binding energy per nucleon for ¹²⁰₅₀Sn. Mass of proton m_p = 1.00783 U, mass of neutron m_n = 1.00867 U and mass of tin nucleus m_sn = 119.902199 U. (take 1U = 931 MeV)

(1) 9.0 MeV

(2) 8.5 MeV

(3) 8.0 MeV

(4) 7.5 MeV

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18/09/2020 6:41 pm

nikhil04

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(2) 8.5 MeV

Explanation:

Binding energy = (ΔM)C² = (ΔM) 931

put the value of ΔM

BE = 8.5 MeV

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Find the Binding energy per nucleon for 120^50Sn. Mass of proton mp = 1.00783 U, mass of neutron mn = 1.00867 U

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