Notifications
Clear all
0
20/09/2020 12:30 pm
Topic starter
An object of mass m is suspended at the end of a massless wire of length L and area of cross-section, A. Young modulus of the material of the wire is Y. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is :
(1) f = 1/2π√mL/YA
(2) f = 1/2π√YL/mA
(3) f = 1/2π√mA/YL
(4) f = 1/2π√YA/mL
1 Answer
0
20/09/2020 12:32 pm
(4) f = 1/2π√YA/mL
Explanation:
f = f = 1/2π√k/m
= 1/2π(√(YA/mL)