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10/01/2022 1:09 pm
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A tuning fork is vibrating at 250 Hz. The length of the shortest closed organ pipe that will resonate with the tuning fork will be _____ cm.
(Take speed of sound in air as 340 ms-1)
1 Answer
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10/01/2022 1:13 pm
\(\frac{\lambda}{4}\) = ℓ
⇒ λ = 4ℓ
f = \(\frac{V}{\lambda}\) = \(\frac{V}{4 \ell}\)
⇒ 250 = \(\frac{340}{4 \ell}\)
⇒ ℓ = \(\frac{34}{4 \times 25}\) = 0.34 m
ℓ = 34 cm