Notifications
Clear all
0
09/01/2022 8:19 pm
Topic starter
A player kicks a football with an initial speed of 25 ms-1 at an angle of 45º from the ground. What are the maximum height and the time taken by the football to reach the highest point during motion? (Take g = 10 ms-2)
(1) hmax = 10 m T = 2.5 s
(2) hmax = 15.625 m T = 3.54 s
(3) hmax = 15.625 m T = 1.77 s
(4) hmax = 3.54 m T = 0.125 s
1 Answer
0
09/01/2022 8:23 pm
Correct answer: (3) hmax = 15.625 m T = 1.77 s
Explanation:
H = \(\frac{U^2 sin^2 \theta}{2g}\)
= \(\frac{(25)^2(sin45)^2}{2 \times 10}\)
= 15.625 m
T = \(\frac{U sin \theta}{g}\)
= \(\frac{25 \times sin 45°}{10}\)
= 2.5 x 0.7
= 1.77 s