A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing at a rate of 102A s–1. The value of the potential difference Vp – VQ, (in volts) at that instant is 2s.png

Vp - L dI/dt - 30 + RI = VQ Vp - VQ = + 50 x 10-3 x 102 + 30 - 1 x 2 = +5 + 30 - 2 = 33

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A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing

Physics

Last Post by nikhil04 4 years ago

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20/09/2020 2:12 pm

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aditi07

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A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing at a rate of 10²A s^–1. The value of the potential difference V_p – V_Q, (in volts) at that instant is

2s.png

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20/09/2020 2:16 pm

nikhil04

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V_p - L dI/dt - 30 + RI = V_Q

V_p - V_Q = + 50 x 10^-3 x 10² + 30 - 1 x 2

= +5 + 30 - 2 = 33

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