[Solved] A parallel plate capacitor of capacitance 200 µF is connected to a battery of 200 V. A dielectric slab of dielectric constant 2 is now inserted
1
16/02/2022 12:03 pm
Topic starter
A parallel plate capacitor of capacitance 200 µF is connected to a battery of 200 V. A dielectric slab of dielectric constant 2 is now inserted into the space between plates of capacitor while the battery remain connected. The change in the electrostatic energy in the capacitor will be_____J.
Answer
Add a comment
Add a comment
Topic Tags
1 Answer
1
16/02/2022 12:05 pm
ΔU = \(\frac{1}{2}(ΔC)V^2\)
ΔU = \(\frac{1}{2}(KC C)V^2\)
ΔU = \(\frac{1}{2}(2  1)CV^2\)
ΔU = \(\frac{1}{2}\)x 200 x 10^{6} x 200 x 200
ΔU = 4 J
Add a comment
Add a comment
Forum Jump:
Related Topics

A resistor dissipates 192 J of energy in 1 s when a current of 4A is passed through it. Now, when the current is doubled, the amount of thermal energy dissipated in 5 s in______J.
2 years ago

Crosssection view of a prism is the equilateral triangle ABC in the figure. The minimum deviation is observed using this prism when the angle of incidence is equal to the prism angle.
2 years ago

At very high frequencies, the effective impedance of the given circuit will be______Ω.
2 years ago

A sample of gas with γ = 1.5 is taken through an adiabatic process in which the volume is compressed from 1200 cm^3 to 300 cm^3. If the initial pressure is 200 kPa.
2 years ago

The diameter of a spherical bob is measured using vernier callipers. 9 divisions of the main scale, in the vernier callipers, are equal to 10 divisions of vernier scale. One main scale division is 1 mm.
2 years ago
Forum Information
 321 Forums
 27.3 K Topics
 53.8 K Posts
 0 Online
 12.4 K Members
Our newest member: Stripchat
Forum Icons:
Forum contains no unread posts
Forum contains unread posts
Topic Icons:
Not Replied
Replied
Active
Hot
Sticky
Unapproved
Solved
Private
Closed