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24/01/2022 2:21 pm
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A moving proton and electron have the same deBroglie wavelength. If K and P denote the K.E. and momentum respectively. Then choose the correct option:
(1) Kp < Ke and Pp = Pe
(2) Kp = Ke and Pp = Pe
(3) Kp < Ke and Pp < Pe
(4) Kp > Ke and Pp = Pe
1 Answer
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24/01/2022 2:26 pm
Correct answer: (1) Kp < Ke and Pp = Pe
Explanation:
λp = \(\frac{h}{P_p}\)
λe = \(\frac{h}{P_e}\)
∵ λp = λe
⇒ Pp = Pe
(K)p = \(\frac{P_P^2}{2m_P}\)
(K)e = \(\frac{P_e^2}{2m_e}\)
Kp < Ke and Pp = Pe