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21/01/2022 3:20 pm
Topic starter
A helicopter is flying horizontally with a speed 'v' at an altitude 'h' has to drop a food packet for a man on the ground. What is the distance of helicopter from the man when the food packet is dropped?
(1) \(\sqrt{\frac{2ghv^2 + 1}{h^2}}\)
(2) \(\sqrt{2ghv^2 + h^2}\)
(3) \(\sqrt{\frac{2v^2h}{g}+h^2}\)
(4) \(\sqrt{\frac{2gh}{v^2}} + h^2\)
1 Answer
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21/01/2022 3:23 pm
Correct answer: (3) \(\sqrt{\frac{2v^2h}{g}+h^2}\)
Explanation:
R = \(\sqrt{\frac{2h}{g}}.v\)
D = \(\sqrt{R^2 + h^2}\)
= \(\sqrt{\Big(\sqrt{\frac{2h}{g}}.v\Big)^2 +h^2}\)
D = \(\sqrt{\frac{2v^2h}{g}+h^2}\)