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08/02/2022 3:32 pm
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A current of 1.5 A is flowing through a triangle, of side 9 cm each. The magnetic field at the centroid of the triangle is
(Assume that the current is flowing in the clockwise direction.)
(1) 3 × 10–7 T, outside the plane of triangle
(2) 2√3 × 10–7 T, outside the plane of triangle
(3) 2√3 × 10–5 T, inside the plane of triangle
(4) 3 × 10–5 T, inside the plane of triangle
1 Answer
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11/02/2022 4:28 pm
Correct answer: (4) 3 × 10–5 T, inside the plane of triangle
Explanation:
B = 3\(\Big[\frac{μ_0i}{4 \pi r}(sin 60° + sin60°)\Big]\)
tan 60° = \(\frac{\frac{\ell}{2}}{r}\)
where r = \(\frac{9 \times 10^{-2}}{2\sqrt3}\)M
∴ B = 3 x 10–5 T
Current is flowing in clockwise direction so, B is inside plane of triangle by right hand rule.