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A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to :

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A cube of metal is subjected to a hydrostatic pressure 4GPa. The percentage change in the length of the side of the cube is close to : (Given bulk modulus of metal, B = 8 × 1010 Pa)

(1) 1.67

(2) 5

(3) 20

(4) 0.6

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(1) 1.67

Explanation:

ΔP = (B)Δv/v = B x 3 ΔL/L

Putting the value of ΔP and B we get ΔL/L x 100 = 1.67

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