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17/09/2020 1:01 pm
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A cricket ball of mass 0.15 kg is thrown vertically up by a bowling machine so that it rises to a maximum height of 20 m after leaving the machine. If the part pushing the ball applies a constant force F on the ball and moves horizontally a distance of 0.2 m while launching the ball, the value of F (in N) is (g = 10 ms–2)
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17/09/2020 1:03 pm
From work energy theorem F(0.2) - mg(20) = 0
F = mg(20)/0.2
= mg(200/2)
= 0.15 x 10 x 200/2
= 150.00 N