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A conducting wire of length 24a is used to form two setups of coils, first in the form of a square of side a and second in the form of an equilateral triangle of side a. Find the ratio of the magnetic moment of the coil in two cases?

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A conducting wire of length 24a is used to form two setups of coils, first in the form of a square of side a and second in the form of an equilateral triangle of side a. Find the ratio of the magnetic moment of the coil in two cases?

(a) \(\frac{\sqrt 3}{1}\)

(b) \(\frac{\sqrt 2}{1}\)

(c) \(\sqrt{\frac{3}{5}}\)

(d)\(\sqrt{\frac{5}{3}}\)

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Correct answer: (a) \(\frac{\sqrt 3}{1}\)

Explanation:

4anr = 24a

Thus, n1 = 6 turns

3anz = 24 ⇒ nz = 8 turns

 figure.png

\(\frac{M_1}{M_2}\) = \(\frac{n_1iA_1}{n_2iA_2}\)

= \(\frac{6 \times 1^2}{8 \times a^2 \times \frac{\sqrt3}{4}}\)

= \(\frac{\sqrt 3}{1}\)

This post was modified 3 years ago 2 times by Reyana09
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