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17/09/2020 1:13 pm
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A calorimeter of water equivalent 20 g contains 180 g of water at 25°C. 'm' grams of steam at 100°C is mixed in it till the temperature of the mixture is 31°C. The value of 'm' is close to (Latent heat of water = 540 cal g–1, specific heat of water = 1 cal g–1 °C–1)
(1) 2
(2) 4
(3) 3.2
(4) 2.6
1 Answer
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17/09/2020 1:15 pm
Correct answer: (1) 2
Explanation:
(200) (31 – 25) = m × 540 + m(1) (69)
1200 = m(609)
m ≈ 2