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19/09/2020 11:16 am
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A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the wood. The rise of temperature of the bullet if the specific heat of its material is 0.030 cal (g–ºC) (1 cal = 4.2 × 107 ergs) close to :
(1) 38.4ºC
(2) 83.3ºC
(3) 87.5ºC
(4) 119.2ºC
1 Answer
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19/09/2020 11:21 am
(3) 87.5ºC
Explanation:
As per given condition
1/2 x 1/2 mv2 = (msΔT)
Δt = V2/4s
= 210 x 210/4 x 4.2 x 0.3 x 1000 = 87.5ºC