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16/09/2020 5:22 pm
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A beam of protons with speed 4 × 105 ms–1 enters a uniform magnetic field of 0.3T at an angle of 60º to the magnetic field. the pitch of the resulting helical path of protons is close to :
(Mass of the proton = 1.67 × 10–27 kg, charge of the proton = 1.69 × 10–19 C)
(1) 12 cm
(2) 2 cm
(3) 4 cm
(4) 5 cm
1 Answer
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16/09/2020 5:26 pm
Correct answer: (3) 4 cm
Explanation:
Pitch = (Vcosθ)T
= (Vcosθ)2πm/eB
= (4 x 105 cos60°) 2π/0.3 x 10(1.67 x 10-27/1.69 x 1019)
= 4 cm