Notifications
Clear all
1
22/12/2021 1:27 pm
Topic starter
ρcu = 12µΩ/cm, ρNi = 51µΩ/cm. If both conductors have equal length, diameter 2 mm each and have equivalent resistance of 3n, find I?
1 Answer
1
22/12/2021 1:34 pm
\(\frac{1}{3}\) = \(\frac{1}{R_{Cu}} + \frac{1}{R_{Fe}}\);
Rcu = \(\frac{12 \ell}{\pi} \times 10^2\)
RNi = \(\frac{51 \ell}{\pi} \times 10^2\)
\(\frac{1}{3}\) = \(\frac{\pi}{100 \ell}\)\(\Big[\frac{1}{12} +\frac{1}{51}\Big]\)
= \(\frac{\pi}{100 \ell}\)x \(\frac{63}{612}\)
\(\ell\) = \(\frac{\pi \times 63}{204 \times 100}\)
= \(\frac{21 \pi}{68}\)cm ≈ 0.97 cm