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The coach of a cricket team buys 3 bats and 6 balls for Rs.3900. Later, she buys another bat and 3 more balls of the same kind for Rs.1300.

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The coach of a cricket team buys 3 bats and 6 balls for Rs.3900. Later, she buys another bat and 3 more balls of the same kind for Rs.1300. Represent this situation algebraically and geometrically.

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Let us assume that the cost of a bat be ‘Rs x’

And, the cost of a ball be Rs y’

According to the question, the algebraic representation is

3x+6y = 3900

And x+3y = 1300

For, 3x+6y = 3900

Or x = (3900-6y)/3

The solution table is

x → 300, 100, 700

y → 500, 600, 300

For, x+3y = 1300

Or x = 1300-3y

The solution table is

x → 400, 100, 700

y → 300, 400, 200

The graphical representation is as follows.

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