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Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

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Half the perimeter of a rectangular garden, whose length is 4 m more than its width, is 36 m. Find the dimensions of the garden.

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Let us consider.

The width of the garden is x and length is y.

Now, according to the question, we can express the given condition as

y – x = 4 and

y + x = 36

Now, taking y – x = 4 or y = x + 4

x \(\rightarrow\) 0, 8, 12

y \(\rightarrow\) 4, 12, 16

For y + x = 36, y = 36 – x

x \(\rightarrow\) 0, 36, 36

y \(\rightarrow\) 36, 0, 20

The graphical representation of both the equation is as follows

From the graph you can see, the lines intersects each other at a point(16, 20). Hence, the width of the garden is 16 and length is 20.
This post was modified 4 years ago by Raavi Tiwari
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