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24/10/2021 7:24 pm
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A train travelling at 20 m s-1 accelerates at 0.5 m s-2 for 30 s. How far will it travel in this time?
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24/10/2021 7:27 pm
Initial velocity, u = 20 m/s
Time, t = 30 s
Acceleration, a = 0.5 m/s2
Distance travelled is
s = \(ut + \frac{1}{2}at^2\)
s = 20 x 30 + \(\frac{1}{2}\) x 0.5 x 30 x 30
s = 600 + 225 = 825 m