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24/10/2021 6:06 pm
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A train starting from rest moves with a uniform acceleration of 0.2 m/s2 for 5 minutes. Calculate the speed acquired and the distance travelled in this time.
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24/10/2021 6:14 pm
Initial velocity, u = 0 m/s
Final velocity, v = ?
Acceleration, a = 0.2 m/s2
Time, t = 5 min = 5 x 60 = 300 sec
Using, v = u + at
v = 0 + 0.2 x 300 = 60m/s
And the distance travelled is
s = \(ut + \frac{1}{2}at^2\)
s = 0 x 300 + \(\frac{1}{2}\)x 0.2 x 300 x 300
s = 0 + 9000 = 9000 m = 9 km