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24/10/2021 5:57 pm
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A motorcycle moving with a speed of 5 m/s is subjected to an acceleration of 0.2 m/s2. Calculate the speed of the motorcycle after 10 seconds, and the distance travelled in this time.
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24/10/2021 6:00 pm
Initial velocity, u = 5 m/s
Final velocity, v = ?
Acceleration, a = 0.2m/s2
Time, t = 10 sec
Using, v = u + at
v = 5 + 0.2 x 10
v = 5 + 2 = 7 m/s
Now distance travelled in time is calculated;
Using, s = \(ut + \frac{1}{2}at^2\)
s = \(5 \times 10 + \frac{1}{2}\times 0.2 \times 10 \times 10\)
s = 50 + 10 = 60 m