Notifications
Clear all
Motion
1
Posts
2
Users
0
Likes
319
Views
0
24/10/2021 6:00 pm
Topic starter
A bus running at a speed of 18 km/h is stopped in 2.5 seconds by applying brakes. Calculate the retardation produced.
1 Answer
0
24/10/2021 6:05 pm
Initial velocity, u = 18 km/h
Final velocity, v = 0 m/s
Time, t = 2.5 sec
Acceleration, a = ?
Using, v = u + at
Initial velocity, u = 18 km/h
u = 18 x \(\frac{1000}{3600}\)
= \(\frac{18000}{3600}\) m/s
= 5 m/s
Final velocity, v = 0 m/s
Time, t = 2.5 sec
Acceleration, a = ?
Using, v = u + at
a = \(\frac{v -u}{t}\) = \(\frac{0-5}{2.5}\)
= -2 m/s2
So, retardation is 2m/s2.