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Linear Equations in One Variable
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04/08/2021 11:04 am
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The sum of three consecutive multiples of 8 is 888. Find the multiples.
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04/08/2021 11:06 am
Let the three consecutive multiples of 8 be 8x, 8(x+1) and 8(x+2).
According to the question,
8x + 8(x+1) + 8(x+2) = 888
⇒ 8 (x + x+1 + x+2) = 888 (Taking 8 as common)
⇒ 8 (3x + 3) = 888
⇒ 3x + 3 = \(\frac{888}{8}\)
⇒ 3x + 3 = 111
⇒ 3x = 111 – 3
⇒ 3x = 108
⇒ x = \(\frac{108}{3}\)
⇒ x = 36
Thus, the three consecutive multiples of 8 are:
8x = 8 × 36 = 288
8(x + 1) = 8 × (36 + 1)
= 8 × 37 = 296
8(x + 2) = 8 × (36 + 2)
= 8 × 38 = 304