Base of isosceles triangle = 4/3 cm

Perimeter of triangle =4\(\frac{2}{15}\)image cm = \(\frac{62}{15}\)

Let the length of equal sides of triangle be x.

According to the question,

4/3 + x + x = \(\frac{62}{15}\) cm

⇒ 2x = \(\frac{62}{15}\) - \(\frac{4}{3}\)cm

⇒ 2x = (62 – 20)/15 cm

⇒ 2x = 42/15 cm

⇒ x = (42/30) × 1/2

⇒ x = 42/30 cm

⇒ x = 7/5 cm

The length of either of the remaining equal sides are 7/5 cm.