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The image of a candle flame placed at a distance of 45 cm from a spherical lens is formed on a screen placed at a distance of 90 cm from the lens. Identify the type of lens and calculate its focal length. If the height of the flame is 2 cm, find the ...

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The image of a candle flame placed at a distance of 45 cm from a spherical lens is formed on a screen placed at a distance of 90 cm from the lens. Identify the type of lens and calculate its focal length. If the height of the flame is 2 cm, find the height of its image.

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Nature of spherical lens = convex lens

Given: u = -45 cm, v = +90 cm

h1 = +2 cm

Using lens formula,

1/f = 1/v - 1/u

= 1/90 - 1/-45 = 1/90 + 1/45

= 1 + 2/90 = 3/90 = 1/30

∴ f = + 30 cm

So, focal length of convex lens is 30 cm.

Again,

m = h2/h1 = v/u

h2 = v/u x h1 = 90/-45 x 2

= -4 cm

So, height of image is 4 cm. Negative sign indicates that it is formed below the principal axis.

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