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07/01/2021 4:32 pm
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A stone is thrown vertically upward with an initial velocity of 40 m/s. Taking g = 10 m/s-2, find the maximum height reached by the stone. What is the net displacement and the total distance covered by the stone?
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07/01/2021 4:37 pm
Here, u = 40 m/s, g = -10 m/s2
h = ? v = 0
From v2 - u2 = 2gh,
0 - (40)2 = 2 (-10)h
or h = \(\frac{40 \times 40}{20}\) = 80 m
As final position of the stone coincides with its initial position, net displacement = 0
Total distance covered by the stone = h + h = 80m + 80m = 160 m