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07/01/2021 4:25 pm
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A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.
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07/01/2021 4:31 pm
Initial velocity, u = 0 ms-1
Final velocity, v = ?
Height of the tower, h = 19.6 m
Acceleration due to gravity, g = 9.8 ms-2
Using the equation, v2 - u2 = 2gs = 2gh
v2 - 0 = 2 x 9.8 ms-2 x 19.6 m
v2 = 19.6 ms-2 x 19.6 m
v2 = (19.6)2 m2s-2
or v = 19.6 ms-1