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Force and Laws of Motion
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31/10/2021 6:54 pm
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A 60 g bullet fired from a 5 kg gun leaves with a speed of 500 m/s. Find the speed (velocity) with which the gun recoils (jerks backwards).
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31/10/2021 6:56 pm
Mass of bullet, m1 = 60g = 0.06 kg
Velocity of bullet v1 = 500 m/s
Mass of gun m2 = 5 kg
Recoil velocity v2
According to the law of conservation of momentum
m1 x v1 = m2 x v2
0.06 x 500 = 5 x v2
v2 = \(\frac{0.06 \times 500}{5}\)
= 6 m/s