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Force and Laws of Motion
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31/10/2021 6:57 pm
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A 10 g bullet travelling at 200 m/s strikes and remains embedded in a 2 kg target which is originally at rest but free to move. At what speed does the target move off?
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31/10/2021 7:01 pm
Mass of bullet, m1 = 10g = 0.01 kg
Velocity of bullet v1 = 200 m/s
Mass of block with the bullet as bullet gets embedded in it,
m2 = 2 + 0.01 = 2.01 kg
Recoil velocity v2
According to the law of conservation of momentum
m1 x v1 = m2 x v2
0.01 x 200 = 2.01 x v2
v2 = \(\frac{0.01 \times 200}{2.01}\)
= 0.99 m/s