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07/10/2020 6:08 pm
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One mole of CH3COOH and one mole of C2H5OH reacts to produce 2/3 mole of CH3COOC2H5. The equilibrium constant is :
(a) 2
(b) +2
(c) -4
(d) +4
1 Answer
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07/10/2020 6:15 pm
(d) +4
Explanation:
CH3COOH + C2H5OH → CH3COOC2H5 + H2O
At start 1 mole 1 mole 0 0
At equb. 1- 2/3 1- 2/3 2/3 2/3
Let the total volume = V L
∴ [CH3COOH] = 1/3V mol/L
[C2H5OH] = 1/3 V mol/L
[CH3COOC2H5] = 2/3 V mol/L
[H2O] = 2/3 V mol/L
∴ K = (2/3 V x 2/3 V)/(1/3V x 1/3 V) = 4