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07/10/2020 5:41 pm
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The equilibrium constant for the following reaction will be:
3A + 2B → C
(a) [3A][2B]/[C]
(b) [C]/[3A][2B]
(c) [C]/[A]2[B]2
(d) [C]/[A]3[B]2
1 Answer
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07/10/2020 5:43 pm
(d) [C]/[A]3[B]2
Explanation:
Equilibrium constant, K = [C]/[A]3[B]2