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20/10/2021 11:07 am
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Zirconium phosphate [Zr3(PO4)4] dissociates into three zirconium cations of charge +4 and four phosphate anions of charge -3. If molar solubility of zirconium phosphate is denoted by S and its solubility product by Ksp then which of the following relationship between S and Ksp is correct?
(a) S = \(\frac{K_{sp}}{(6912)^{\frac{1}{7}}}\)
(b) S = \((\frac{K_{sp}}{144})^{\frac{1}{7}}\)
(c) S = \((\frac{K_{sp}}{6912})^{\frac{1}{7}}\)
(d) S = \((\frac{K_{sp}}{6912})^7\)
1 Answer
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20/10/2021 11:26 am
Correct answer: (c) S = \((\frac{K_{sp}}{6912})^{\frac{1}{7}}\)
Explanation:
[Zr3(PO4)4] ⇌ 3Zr4+ + 4PO43-
3S 4S
Ksp = (3S)3(4S)4
= 27 S3 x 256 S4
= 6912 S7
∴ S = \((\frac{K_{sp}}{6912})^{\frac{1}{7}}\)