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25/10/2021 12:48 pm
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The dissociation constants of a weak acid HA and weak base BOH are 2 × 10-5 and 5 × 10-6 respectively. The equilibrium constant for the neutralisation reaction of the two is
(a) 1.0 × 104
(b) 1.0 × 10-4
(c) 1.0 × 10-10
(d) 2.5 × 10-1
1 Answer
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25/10/2021 12:53 pm
Correct answer: (a) 1.0 × 104
Explanation:
HA + BOH ⇌ BA + H2O
∴ KH = \(\frac{K_w}{K_a \times K_b}\)
The inverse of KH is Kc = \(\frac{K_a \times K_b}{K_w}\)
= \(\frac{2 \times 10^{-5} \times 5 \times 10^{-6}}{1 \times 10^{-14}}\)
= 1.0 × 104