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Equilibrium
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12/10/2021 11:16 am
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When CO2 dissolves in water, the following equilibrium is established
CO2 + 2H2O ⇌ H3O+ + HCO3-
for which the equilibrium constant is 3.8 × 10-7 and pH = 6.0. The ratio of [HCO3-] to [CO2] would be
(a) 3.8 × 10-13
(b) 3.8 × 10-1
(c) 6.0
(d) 13.4
1 Answer
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12/10/2021 11:20 am
Correct answer: (b) 3.8 × 10-1
Explanation:
CO2 + 2H2O ⇌ H3O+ + HCO3-
Kc = \(\frac{[H_3O^+][HCO_3^-]}{[CO_2]}\)
\(\frac{[HCO_3^-]}{[CO_2]}\) = \(\frac{3.8 \times 10^{-7}}{10^{-6}}\)
= 3.8 × 10-1