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19/10/2021 9:41 am
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What is the percentage hydrolysis of NaCN in N/80 solution when the dissociation constant for HCN is 1.3 × 10-9 and Kw = 1.0 × 10-14
(a) 2.48
(b) 5.26
(c) 8.2
(d) 9.6
1 Answer
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19/10/2021 9:45 am
Answer: (a) 2.48
Explanation:
α = \(\sqrt{\frac{K_w}{K_a \times c}}\)
= \(\sqrt{\frac{10^{-14}}{1.3 \times 10^{-9}\times \frac{1}{80}}}\)
= 2.48%
This post was modified 3 years ago by admin