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The solubility product of Ag2CrO4 is 32 x 10^-12. What is the concentration of CrO4^2- ions in that solution

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The solubility product of Ag2CrO4 is 32 x 10-12. What is the concentration of CrO42- ions in that solution (in g L-1)

(a) 2 × 10-4

(b) 8 × 10-4

(c) 8 × 10-8

(d) 16 × 10-4

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Correct answer: (a) 2 × 10-4

Explanation:

For ternary electrolyte; solubility

= \(\Big(\frac{K_{sp}}{4}\Big)^{\frac{1}{3}}\)

= \(\Big(\frac{32 \times 10^{-12}}{4}\Big)^{\frac{1}{3}}\)

= 2 x 10-4

This post was modified 3 years ago by Mayank1444
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