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Equilibrium
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24/10/2021 10:23 am
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The percentage hydrolysis of 0.15 M solution of ammonium acetate, Ka for CH3COOH is 1.8 × 10-5 and Kb for NH3 is 1.8 × 10-5
(a) 0.55
(b) 4.72
(c) 9.38
(d) 5.56
1 Answer
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24/10/2021 10:28 am
Correct answer: (a) 0.55
Explanation:
α = \(\sqrt{\frac{K_w}{K_a \times K_b}}\)
= \(\sqrt{\frac{1 \times 10^{-14}}{1.8 \times 10^{-5} \times 1.8 \times 10^{-5}}}\)
= 0.55 %