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19/10/2021 9:47 am
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The dissociation constant of 0.1 M acetic acid solution is 1.8 × 10-5. If 1 L of this solution is mixed with 0.05 mole of HCl, what will be pH of mixture? [log 5 = 0.7]
(a) 1.3
(b) 2.6
(c) 1.9
(d) 3.4
1 Answer
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19/10/2021 9:50 am
Correct answer: (a) 1.3
Explanation:
The pH of mixture is due to the HCl only, because CH3COOH is negligibly ionised due to common ion effect. Thus,
[H+] = 0.05 M = 5 × 10-2 M
pH = -1og (5 × 10-2) = -[log 5 + log 10-2]
pH = 1.3