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The concentration of hydroxyl ion in a solution left after mixing 100 mL of 0.1 M MgCl2 and 100 mL of 0.2 M NaOH

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The concentration of hydroxyl ion in a solution left after mixing 100 mL of 0.1 M MgCl2 and 100 mL of 0.2 M NaOH

(Ksp of Mg(OH)2 = 1.2 x 10-11) is

(a) 2.8 x 10-4

(b) 2.8 × 10-3

(c) 2.8 x 10-2

(d) 2.8 x 10-5

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Correct answer: (a) 2.8 x 10-4

Explanation:

MgCl2 + 2NaOH → Mg(OH)2 + 2NaCl

100x0.1  100x0.2    0          0  Initial moles

0           0              10        20 After mixing

∴ Ksp = \(\Big[\frac{10}{200}\Big]\)\(\Big[\frac{20}{200}\Big]^2\)

= 5 x 10-4

But actually Ksp of Mg(OH)2 = 1.2 x 10-11

∴ 4S3 = 1.2 x 10-11

Find S then [OH-] = 2S which is 2.8 x 10-4

This post was modified 3 years ago by Mayank1444
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