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08/10/2021 12:06 pm
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One mole of SO3 was placed in a one litre reaction flask at a given temperature when the reaction equilibrium was established in the reaction.
2SO3 ⇌ 2SO2 + O2
The vessel was found to contain 0.6 mole of SO2. The value of the equilibrium constant is
(a) 0.36
(b) 0.675
(c) 0.45
(d) 0.54
1 Answer
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08/10/2021 12:29 pm
Correct answer: (b) 0.675
Explanation:
2SO3 ⇌ 2SO2 + O2
Initial 1 0 0
At equilibrium 1 - 2α 2α α
∴ 2α = 0.6,
∴ α = 0.3
[SO3] = 1 -2α = 1 - 0.6 = 0.4
[SO2] = 2α = 0.6
[O2] = α = 0.3
Keq = \(\frac{α \times(2α)^2}{(1 - 2α)^2}\)
= \(\frac{0.3 \times 0.6 \times 0.6}{0.4 \times 0.4}\)
= 0.675