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12/10/2021 10:54 am
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One mole of O2(g) and two moles of SO2(g) were heated in a closed vessel of one-litre capacity at 1098 K. At equilibrium 1.6 moles of SO3(g) were found. The equilibrium constant Kc of the reaction would be
(a) 30
(b) 40
(c) 80
(d) 60
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12/10/2021 10:59 am
Correct answer: (c) 80
Explanation:
O2(g) + 2SO2 ⇌ 2SO3
at t = 0 1 2 0
at equil. (1 - α) 2(1 - α) 2α
Given at equilibrium
2α = 1.6
α = 0.8
Kc = \(\frac{(2α)^2}{(1 - α)(2 -2α)^2}\)
= \(\frac{(0.8)^2}{(1-0.8)(1-0.8)^2}\)
= \(\frac{0.64}{0.008}\)
Kc = 80