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09/10/2021 11:48 am
Topic starter
(1) N2(g) + 3H2(g) ⇌ 2NH3(g), K1
(2) N2(g) + O2(g) ⇌ 2NO(g), K2
(3) H2(g) + 1/2O2(g) ⇌ H2O(g), K3
The equation for the equilibrium constant of the reaction
2NH3(g) + 5/2O2(g) ⇌ 2NO(g) + 3H2O(g), (K4) in terms of K1, K2 and K3 is:
(a) \(\frac{K_1.K_2}{K_3}\)
(b) \(\frac{K_1.K_3^2}{K_2}\)
(c) K1K2K3
(d) \(\frac{K_2.K_3^3}{K_1}\)
1 Answer
1
09/10/2021 11:50 am
Correct answer: (d) \(\frac{K_2.K_3^3}{K_1}\)
Explanation:
To calculate the value of K4 in the given equation we should apply:
eqn. (2) + eqn.(3) × 3 - eqn. (1)
Hence K4 = \(\frac{K_2.K_3^3}{K_1}\)