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10/10/2021 11:37 am
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In reaction A + 2B ⇌ 2C + D, initial concentration of B was 1.5 times of [A], but at equilibrium the concentrations of A and B became equal. The equilibrium constant for the reaction is:
(a) 8
(b) 4
(c) 12
(d) 6
1 Answer
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10/10/2021 11:42 am
Correct answer: (b) 4
Explanation:
A + 2B ⇌ 2C + D
a 1.5a 0 0
(a-x) (1.5a-2x) 2x x
Hence Kc = \(\frac{(2x)^2 \times x}{(a -x)(1.5a - 2x)^2}\)
Given, at equilibrium
∴ (a - x) = (1.5a - 2x)
∴ a = 2x
On solving Kc = 4