Notifications
Clear all
0
08/10/2021 12:51 pm
Topic starter
If K1 and K2 are respective equilibrium constants for the two reactions
XeF6(g) + H2O(g) ⇌ XeOF4(g) + 2HF(g)
XeO4(g) + XeF6(g) ⇌ XeOF4(g) + XeO3F2(g)
the equilibrium constant for the reaction
XeO4(g) + 2HF(g) ⇌ XeO3F2(g) + H2O(g) will be
(a) \(\frac{K_1}{K_2}\)
(b) K1.K2
(c) \(\frac{K_1}{K_2}\)
(d) \(\frac{K_2}{K_1}\)
1 Answer
0
08/10/2021 12:55 pm
Correct answer: (d) \(\frac{K_2}{K_1}\)
Explanation:
K = K2 x \(\frac{1}{K_1}\)
= \(\frac{K_2}{K_1}\)