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08/10/2021 12:59 pm
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If 1.0 mole of I2 is introduced into 1.0 litre flask at 1000 K, at equilibrium (Kc = 10-6), which one is correct
(a) [I2(g)] > [I-(g)]
(b) [I2(g)] < [I-(g)]
(c) [I2(g)] = [I- (g)]
(d) [I2(g)] = 1/2[I-(g)]
1 Answer
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08/10/2021 1:04 pm
Correct answer: (a) [I2(g)] > [I-(g)]
Explanation:
I2 ⇌ 2I-
1-x 2x
Kc = \(\frac{(2x)^2}{(1-x)}\) = 10-6
Soln. shows that (1 - x) > 2x
∴ [I2(g)] > [I-(g)]