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Given (i) HCN(aq) + H2O(l) ⇌ H3O^+(aq) + CN^-(aq) Ka = 6.2 x 10^-10 (ii) CN^-(aq) + H2O(l) ⇌ HCN(aq) + OH^-(aq) Kb = 1.6 x 10^-5 These equilibrium show the following order of the relative base strength
Equilibrium
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12/10/2021 11:49 am
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Given
(i) HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN-(aq) Ka = 6.2 x 10-10
(ii) CN-(aq) + H2O(l) ⇌ HCN(aq) + OH-(aq) Kb = 1.6 x 10-5
These equilibrium show the following order of the relative base strength
(a) OH- > H2O > CN-
(b) OH- > CN- > H2O
(c) H2O > CN- > OH-
(d) CN- > H2O > OH-
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12/10/2021 11:51 am
Correct answer: (b) OH- > CN- > H2O
Explanation:
The more is the value of equilibrium constant, the more is the completion of reaction or more is the concentration of products i.e. the order of relative strength would be
OH- > H2O > CN-
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