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Given (i) HCN(aq) + H2O(l) ⇌ H3O^+(aq) + CN^-(aq) Ka = 6.2 x 10^-10 (ii) CN^-(aq) + H2O(l) ⇌ HCN(aq) + OH^-(aq) Kb = 1.6 x 10^-5 These equilibrium show the following order of the relative base strength

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Given

(i) HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN-(aq) Ka = 6.2 x 10-10

(ii) CN-(aq) + H2O(l) ⇌ HCN(aq) + OH-(aq) Kb = 1.6 x 10-5

These equilibrium show the following order of the relative base strength

(a) OH- > H2O > CN-

(b) OH- > CN- > H2O

(c) H2O > CN- > OH-

(d) CN- > H2O > OH-

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Correct answer: (b) OH- > CN- > H2O

Explanation:

The more is the value of equilibrium constant, the more is the completion of reaction or more is the concentration of products i.e. the order of relative strength would be 

OH- > H2O > CN-

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