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10/10/2021 11:54 am
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For the reaction
NH4HS(g) ⇌ NH3(g) + H2S(g) in a closed flask, the equilibrium pressure is P atm. The standard free energy of the reaction would be
(a) -RT ln p
(b) -RT (ln p - ln 2)
(c) -2 RT ln p
(d) -2 RT (ln p - ln 2)
1 Answer
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10/10/2021 12:01 pm
Answer is (d) -2 RT (ln p - ln 2)
Explanation:
PNH3 = PH2S
= \(\frac{P}{2}\)atm
KP = PNH3PH2S
= \(\Big(\frac{P}{2}\Big)^2\)
= \(\frac{P^2}{4}\)
ΔG = -RTlnKp
= -RT ln\((\frac{P}{2})^2\)
= -2 RT (ln p - ln 2)
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