Notifications
Clear all
0
08/10/2021 12:33 pm
Topic starter
For the equilibrium system
2HX(g) ⇌ H2(g) + X2(g)
the equilibrium constant is 1.0 × 10-5. What is the concentration of HX if the equilibrium concentration of H2 and X2 are 1.2 × 10-3 M, and 1.2 × 10-4 M respectively.
(a) 12 × 10-4 M
(b) 12 × 10-3 M
(c) 12 × 10-2 M
(d) 12 × 10-1 M
1 Answer
0
08/10/2021 12:43 pm
Answer is (c) 12 × 10-2 M
2HX(g) ⇌ H2(g) + X2(g)
At equation, 1.2 x 10-3 M 1.2 x 10-4 M
Keq = \(\frac{[H_2][X_2]}{[HX]^2}\)
10-5 = \(\frac{1.2 \times 10^{-3} \times 1.2 \times 10^{-4}}{[HX]^2}\)
[HX] = \(\sqrt{\frac{1.2 \times 1.2 \times 10^{-7}}{10^{-5}}}\)
= 1.2 x 10-1 M
= 12 x 10-2 M